*/

#include <stdio.h>

#include <stdlib.h>

#include <math.h>

int main (int argc, char **argv)

{

    int N;

    if (argc != 2) {

        printf ("Usage: %s <value>\n", argv[0]);

        return EXIT_FAILURE;

    }

    for (N = 1; N <= atoi (argv[1]) + 1; N++)

        printf ("[2^%d]: %.1f\n", N - 1, pow (2, N - 1));

    return EXIT_SUCCESS;

}